From a504308842d4c4fb4143ff7a8116b64d64e338e8 Mon Sep 17 00:00:00 2001 From: Takuyama Date: Tue, 28 Jan 2025 23:21:06 +0800 Subject: [PATCH] =?UTF-8?q?Update=20and=20rename=202024=E7=A7=8B=E6=9C=9F?= =?UTF-8?q?=E6=9C=AB=E8=80=83=E8=AF=95=E7=AD=94=E6=A1=88=20to=202024?= =?UTF-8?q?=E7=A7=8B=E6=9C=9F=E6=9C=AB=E8=80=83=E8=AF=95=E7=AD=94=E6=A1=88?= =?UTF-8?q?.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- .../24FallFinalExam/2024秋期末考试答案 | 1 - .../24FallFinalExam/2024秋期末考试答案.md | 31 +++++++++++++++++++ 2 files changed, 31 insertions(+), 1 deletion(-) delete mode 100644 信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案 create mode 100644 信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案.md diff --git a/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案 b/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案 deleted file mode 100644 index 7efd0e3..0000000 --- a/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案 +++ /dev/null @@ -1 +0,0 @@ - 设 $G=\{a,b,c,e\}$ 是一个群, $H=\{a,e\}$ 是 $G$ 的子群,写出 $H$ 的所有左陪集 diff --git a/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案.md b/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案.md new file mode 100644 index 0000000..95ba722 --- /dev/null +++ b/信息安全数学基础(二)/24FallFinalExam/2024秋期末考试答案.md @@ -0,0 +1,31 @@ +**设 $G=\{a,b,c,e\}$ 是一个群, $H=\{a,e\}$ 是 $G$ 的子群,写出 $H$ 的所有左陪集** +  将 $G$ 中元素 $g$ 各个代入,计算 $gH$: + +
    +
  1. + $g = e$: + $eH = H$ +
  2. + +
  3. + $g = a$: + $aH = \{ a \cdot a, a \cdot e \} = \{ a^2, a \}$,由于 $G$ 是群,且 $H$ 是子群,$a^2$ 必须是 $G$ 中的元素。 \\ + 故 $a^2 = e$,则: + $aH = \{ e, a \} = H $ +
  4. + +
  5. + $g = b$: + $bH = \{ b \cdot a, b \cdot e \} = \{ ba, b \} $ + 假设 \( ba = c \),则: + $bH = \{ c, b \} $ +
  6. + +
  7. + $g = c$: + $cH = \{ c \cdot a, c \cdot e \} = \{ ca, c \} $ + 假设 \( ca = b \),则: + $cH = \{ b, c \} $ +
  8. + +